VITEEE Exam 2014 - Previous Year Question paper with solutions
Download VITEEE Exam 2014 previous year chemistry question paper with solutions. VIT University conducts VITEEE Exam to get admission for Btech. I have given the correct answers and solution for each and every question and answer for VITEEE Exam 2014 question paper.
To get admission in Vellore Institute of Technology(VIT) for all the campuses (Vellore, Chennai, Bhopal, Amaravati), students got to clear the VITEEE examination, that is one in every of the toughest exams to enter into one in every of the most effective engineering university in an Asian country, VITEEE Exam 2014 previous year question papers with solutions can facilitate students to arrange for the examination.
To get admission in Vellore Institute of Technology(VIT) for all the campuses (Vellore, Chennai, Bhopal, Amaravati), students got to clear the VITEEE examination, that is one in every of the toughest exams to enter into one in every of the most effective engineering university in an Asian country, VITEEE Exam 2014 previous year question papers with solutions can facilitate students to arrange for the examination.
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VITEEE Exam 2014 Question paper with solutions (Part 1)
VITEEE Exam 2014 Question paper with solutions (Part 3)
Download link will be available below
There will be 40 questions out of 120 questions. Remaining questions will be available in the next blog. Correct answer and explanation for each question are available after each question. Download links for this question paper will be available at the end of the page.
VITEEE Exam 2014 Questions with Solution (Part 2)
41. The standard molar heat of formation of ethane, CO₂ and water (l) are respectively -21.1, -94.1 and -68.3 kcal. The standard molar heat of combustion of ethane will be
A) -372 kcal
B) 162 kcal
C) -240 kcal
D) 183.5 kcal
Answer: A) -372 kcal
Explanation: Given, (i) 2C + 3H₂ → C₂H6 ; ΔH = -21.1 (ii) C + O₂ → CO₂ ΔH = -94.1 (iii) H₂ + (1/2)O₂ → H₂O;ΔH = -68.3 Eqs. 2(ii) + 3(iii) - (i) C₂H6 + 3 / 2 O₂ → 2CO₂ + 3H₂O Δx = 2(-94.1) + 3(-68.3)-(-21.1) = -372 kcal
42. The solubility product of Ag₂CrO₄ is 32 * 10-12. What is the concentration of CrO- ₄ ions in that solution?
A) 2 * 10-4 M
B) 16 * 10-4 M
C) 8 * 10-4 M
D) 8 * 10-8 M
Answer: A) 2 * 10-4 M
Explanation:
43. The equivalent conductivity of a solution containing 2.54 g of CuSO₄ per L is 91.0 W-1 cm² eq-1. Its conductivity would be
A) 2.9 * 10-3 Ω-1 cm-1
B) 1.8 * 10-2 Ω-1 cm-1
C) 2.4 * 10-4 Ω-1 cm-1
D) 3.6 * 10-3 Ω-1 cm-1
Answer: A) 2.9 * 10-3 Ω-1 cm-1
Explanation: K = ∧eq ⋅ C = (91 Ω-1cm²eq-1) (2.54 / (159/2*1000) eq.cm-3) = 2.9 * 10-3 Ω-1 cm-1
44. The half-life of two samples is 0.1 and 0.8 s. Their respective concentration is 400 and 50 respectively. The order of the reaction is
A) 0
B) 2
C) 1
D) 4
Answer: B) 2
Explanation: We know that, (t1/2)₁ / (t1/2)₂ = [a₂ / a₁]n-1 where, n = order of the reaction Given, (t1/2) = 0.1s, a₁ = 400 (t1/2)₂ = 0.8s, a₂ = 50 On substituting the values, 0.1 / 0.8 = [50/400]n-1 On taking log both sides log 0.1 / 0.8 = (n-1) log 50/400 log 1/8 = (n - 1)log 1/8 0.90 = (n - 1) 0.90 n - 1 = 1 ⇒ n = 2
45. Which sequence of reactions shows the correct chemical relation between sodium and its compounds?
A) A
B) B
C) C
D) D
Answer: D) D
Explanation:
46. The purest form of iron is
A) pig iron
B) wrought iron
C) cast iron
D) steel
Answer: B) wrought iron
Explanation: Wrought or malleable iron is the purest form of iron
47. Which has the smallest size?
A) Na+
B) Mg2+
C) AI3+
D) P5+
Answer: D) P5+
Explanation: As the nuclear charge per electron is maximum in P5+. Therefore, its size is smallest
48. In the reaction, 8Al + 3Fe₃O ₄ → 4Al2O3 + 9Fe, the number of electrons transferred from the reductant to the oxidant is
A) 8
B) 4
C) 16
D) 24
Answer: D) 24
Explanation: 8AI → 8AI3+ + 24e- 9Fe8/3+ + 24e- → 9Fe
49. The bond angles of NH₃, NH₄+ and NH₂- are in the order
A) NH₂- > NH₃ > NH₄+
B) NH₄+ > NH₃ > NH₂-
C) NH₃ > NH₂- > NH₄+
D) NH > NH₄+ > NH₂-
Answer: B) NH₄+ > NH₃ > NH₂-
50. A gaseous mixture containing He, CH₄ and SO₂ were allowed to effuse through a fine hole then find what molar ratio of gases coming out initially? (Given mixture contains He, CH₄ and SO₂ in 1: 2: 3-mole ratio).
A) √2: √2 : 3
B) 2 : 2 : 3
C) 4: 4 : 3
D) 1 : 1 : 3
Answer: C) 4: 4 : 3
Explanation: n'He / n'CH₄ = 1/2 √16/4 = 1/1 n'He / n'SO₂ = 1/3 √64/4 = 4/3 So, n'He : n'CH₄ : n'SO₂ = 4 : 4 : 3
51. According to Bohr's theory, the angular momentum for an electron of the 3rd orbit is
A) 3 h
B) 1.5 h
C) 9 h
D) 2 h / π
Answer: A) 3 h
Explanation: Angular momentum, mvr = nh / 2Ï€ = 3 * h / 2Ï€ = 1.5h / Ï€ = 3h [ ∴ h = h / 2Ï€]
52. 2.76 g of silver carbonate on being strongly heated yields a residue weighing
A) 3.54 g
B) 3.0 g
C) 1.36 g
D) 2.16 g
Answer: D) 2.16 g
Explanation:
53. The final product (IV) in the sequence of reactions
A) A
B) B
C) C
D) D
Answer: A) A
Explanation:
54. Find
A) A
B) B
C) C
D) D
Answer: A) A
Explanation:
55. Which of the following has an ester linkage?
A) Nylon-66
B) Dacron
C) PVC
D) Bakelite
Answer: B) Dacron
Explanation: When a diacid is condensed with alcohol, the polymer obtained contains an ester linkage
56. Which of the following pairs give positive Tollen's test?
A) Glucose, sucrose
B) Glucose, fructose
C) Hexanal, acetophenone
D) Fructose, sucrose
Answer: B) Glucose, fructose
Explanation: Aldehydes and α - hydroxy ketones give positive Tollen's test. Glucose is a polyhydroxy aldehyde and fructose is an α - hydroxy ketone
57. Peptisation involves
A) precipitation of colloidal particles
B) disintegration of colloidal aggregates
C) evaporation of dispersion medium
D) impact of molecules of the dispersion medium on, the colloidal particles
Answer: B) disintegration of colloidal aggregates
Explanation: Peptisation is a process in which freshly prepared precipitate disintegrates into a colloidal solution
58. Which of the following has the maximum number of unpaired d-electrons?
A) Fe2+
B) Cu+
C) Zn
D) Ni3+
Answer: A) Fe2+
Explanation: Fe2+ = [Ar] 3d64s0 ⇒ 4 unpaired electrons Cu+ [Ar] 3d10 4s0 ⇒ 0 unpaired electron Zn = [Ar] 3d10 4s² ⇒ 0 unpaired electron Ni3+ = [Ar] 3d7 4s0 ⇒ 3 unpaired electrons
59. Iodine is formed when potassium iodide reacts with a solution of
A) ZnSO₄
B) CuSO₄
C) (NH₄)₂SO₄
D) Na₂SO₄
Answer: B) CuSO₄
Explanation:
60. Which of the following does not represent the correct order of the property indicated?
A) Sc3+ > Cr3+ > Fe3+ > Mn3+ --- ionic radii
B) Sc < Ti < Cr < Mn --- density
C) Mn2+ > Ni2+ > Co2+ < Fe2+ --- ionic radii
D) FeO < CaO < MnO < CuO --- basic nature
Answer: A) Sc3+ > Cr3+ > Fe3+ > Mn3+ --- ionic radii
Explanation: Sc3+ > Cr3+ > Fe3+ > Mn3+ , the correct order is Cr3+ > Mn3+ > Fe3+ > Sc3+
61. If the elevation in the boiling point of a solution of 10 g of solute (mol. wt. = 100) in 100 g of water is ΔTb, the ebullioscopic constant of water is
A) 10
B) 100 Tb
C) Δ Tb
D) ΔTb / 10
Answer: C) Δ Tb
Explanation: We know that, ΔTb = 1000 * kb * w / W * M M = 1000 * kb * w / W * ΔTb ΔTb = 1000 * kb * 10 / 100 * 100 ΔTb = kb
62. Which of the following compounds cannot be prepared singly by the Wurtz reaction?
A) C₂H6
B) (CH₃)₂CHCH₃
C) CH₃CH₂CH₂CH₃
D) All of the above can be prepared
Answer: B) (CH₃)₂CHCH₃
Explanation: If two different alkyl halides (R₁ - X and R₂ - X) are used, a mixture of three alkanes is obtained which is difficult to separate
63. Which of the following oxides is strongly basic?
A) TI₂O
B) B₂O₃
C) AI₂O₃
D) Ga₂O₃
Answer: A) TI₂O
Explanation: As we move down the group, the basic nature of the oxides of group 13 elements increases. TI₂O in aqueous solution gives TIOH which is as strong a base as alkali metal hydroxides.
64. In Langmuir's model of adsorption of a gas on a solid surface
A) the rate of dissociation of adsorbed molecules from the surface does not depend on the surface covered
B) the adsorption at a single site on the surface may involve multiple molecules at the same time
C) the mass of gas striking a given area of the surface is proportional to the pressure of the gas
D) the mass of gas striking a given area of the surface is independent of the pressure of the gas
Answer: C) the mass of gas striking a given area of the surface is proportional to the pressure of the gas
Explanation: In Langmuir's adsorption isotherm, the mass of gas striking a given area of the surface is proportional to the pressure of the gas as x / m = k'p / 1 + kp
65. How many sigma and pi-bonds are there in the molecule of dicyanomethylene(CN -- CH = CH -- CN)?
A) 3 sigma and 3 pi
B) 5 sigma and 2 pi
C) 7 sigma and 5 pi
D) 2 sigma and 3 pi
Answer: C) 7 sigma and 5 pi
Explanation:
66. What will be the order of reactivity of the following carbonyl compounds with Grignard's reagent?
A) A
B) B
C) C
D) D
Answer: A) A
Explanation: As the number and the size of the alkyl groups increases, reactivity decreases. Hence the reactivity order is
67. Find
A) A
B) B
C) C
D) D
Answer: D) D
Explanation:
68. Which of the following isomerism is shown by ethyl acetoacetate?
A) Geometrical isomerism
B) Keto-enol tautomerism
C) Enantiomerism
D) Diastereoisomerism
Answer: B) Keto-enol tautomerism
Explanation:
69. Find
A) A
B) B
C) C
D) D
Answer: B) B
Explanation:
70. Among the following the strongest nucleophile is
A) C₂H5SH
B) CH₃COO-
C) CH₃NH₂
D) NCCH₂ -
Answer: A) C₂H5SH
Explanation: Nucleophiles are those substances which can donate a pair of electrons. They can be neutral or negatively charged. The nucleophilic power depends on the tendency of species to donate the electrons. Due to the presence of +/ effect, it increases. Hence, higher the +/ effect, higher the nucleophilic power
71. Which set has a different class of compounds?
A) Tranquillizers-Equanil, heroin, valium
B) Antiseptics-Bithional, Dettol, boric acid
C) Analgesics-Naproxen, morphine, aspirin
D) Bactericidal-Penicillin, aminoglycosides, ofloxacin
Answer: D) Bactericidal-Penicillin, aminoglycosides, ofloxacin
Explanation: Heroin is not a tranquillizer, it is a narcotic analgesic
72. The sodium extract of an organic compound on acidification with acetic acid and addition of lead acetate solution gives a black precipitate. The organic compound contains
A) nitrogen
B) halogen
C) sulphur
D) phosphorus
Answer: A) nitrogen
Explanation: The sulphur containing organic compounds when fused with sodium metal give Na#8322'S which react with lead acetate and forms black ppt of PBS
73. The volume strength of 1.5 N H₂O₂ solution is
A) 16.8 L
B) 8.4 L
C) 4.2 L
D) 5.2 L
Answer: B) 8.4 L
Explanation: Volume strength = 5.6 * normality = 5.6 * 1.5 = 8.4 L
74. CuMnO-₄ + 8H+ + 5e- → Mn2+ + 4H₂O; E° = 1.51 V MnO₂ + 4H+ + 2e- → Mn2+ + 2H₂O; E° = 1.23 V E°MnO₄ | MnO₂ is
A) 1.70 V
B) 0.91 V
C) 1.37 V
D) 0.548 V
Answer: A) 1.70 V
Explanation: For the reaction, MnO- ₄ + 4H+ + 3e- → MnO₂ + 2H₂O -E₃ = -1.51 * 5 + 2 * 1.23 / 3 ∴ e₃ = 1.70 V
75. Metal has a bcc structure and the edge length of its unit cell is 3.04 â„«. The volume of the unit cell in cm³ will be
A) 1.6 * 1021 cm³
B) 2.81 * 10-23 cm³
C) 6.02 * 10-23 cm³
D) 6.6 * 10-24 cm³
Answer: B) 2.81 * 10-23 cm³
Explanation: Volume of unit cell(V) = a³. = (3.04 * 10-8 cm)³ = 2.81 * 10-23 cm³
76. Among [Fe(H₂O)6]3 +, (Fe(CN)6]3-, [Fe(CI)6]3- species, the hybridisation state of the Fe atom are, respectively
A) d²sp³, d²sp³, sp³d²
B) sp³d², d²sp³, d²sp³
C) sp³d², d²sp³, sp³d²
D) None of the above
Answer: B) sp³d², d²sp³, d²sp³
Explanation:
77. Which of the following hydrogen bonds are strongest in vapour phase?
A) HF ...... HF
B) HF ...... HCI
C) HCI ...... HCI
D) HF ...... HI
Answer: A) HF ...... HF
Explanation: A compound having maximum electronegative element will form a strong hydrogen bond
78. The rate constant for the forward reaction. and the backward reaction of hydrolysis of the ester is 1.1 * 10-2 and 1.5 * 10-3 per minute respectively. The equilibrium constant for the reaction is CH₃COOC₂H5 + H₂O ⇌ CH₃COOH + C₂H5OH
A) 33.7
B) 7.33
C) 5.33
D) 33.3
Answer: B) 7.33
Explanation: kf = 1.1 * 10-2 , kb = 1.5 * 10-3 Kc = kf / kb = 1.1 * 10-2 / 1.5 * 10-3 = 7.33
79. 19.85 mL of 0.1 N NaOH reacts with 20 mL of HCl solution for complete neutralisation. The molarity of HCl solution is
A) 9.9
B) 0.99
C) 0.099
D) 0.0099
Answer: C) 0.099
Explanation: Molarity of base = normality / Acidity = 0.1 / 1 = 0.1 M₁V₁ = M₂V₂ 0.1 * 19.85 = M₂ * 20 M₂ = 0.09925 ≈ 0.099
80. A Æ’-shell containing 6 unpaired electrons can exchange
A) 6 electrons
B) 9 electrons
C) 12 electrons
D) 15 electrons
Answer: D) 15 electrons
Explanation:
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